Java Development

[maribou]

I am trying to find the fastest way to draw a bitmap at an arbitrary angle.  Here is what I have so far:

private void drawRotatedBitmap(Graphics graphics, Bitmap bm, int angle, int x, int y) {
  int w = bm.getWidth(); int h = bm.getHeight();
  double a = Math.toRadians(angle);
  int x1 = (int) (x - h * Math.sin(a));
  int y1 = (int) (y + h * Math.cos(a));
  int x2 = (int) (x1 + w * Math.cos(a));
  int y2 = (int) (y1 + w * Math.sin(a));
  int x3 = (int) (x + w * Math.cos(a));
  int y3 = (int) (y + w * Math.sin(a));
  int xPts[] = {x, x1, x2, x3};
  int yPts[] = {y, y1, y2, y3};
  int fAngle = Fixed32.toFP(angle);
  int dvx = Fixed32.cosd(fAngle);
  int dux = -Fixed32.sind(fAngle);
  int dvy = Fixed32.sind(fAngle);         
  int duy = Fixed32.cosd(fAngle);
  graphics.drawTexturedPath(xPts, yPts, null, null, x, y, dvx, dux, dvy, duy, bm);
}

The problem is that drawTexturedPath does exactly what it was designed for: it draws a path.  Could anyone kindly suggest a way of hiding the path part so the rotated image wouldn't have a stroke around it?  Are there other ways to draw a rotated image quicky and with a quality comparable to what drawTexturedPath produces?

[maribou · Accepted solution]

I've found the source of the problem.  Apparently the path is only drawn when you enable polygon anti-aliasing by calling

graphics.setDrawingStyle(Graphics.DRAWSTYLE_AAPOLYGONS, true);

Removing this line solved the problem.

[eichen]

Can anyone explain how to modify this code so that the bitmap is rotated around its center instead of its corner?  I would like it to behave like this code:

http://rim.lithium.com/t5/Java-Development/How-to-rotate-an-image/m-p/188685

...but faster.

Thanks in advance