Java Development

[nimesh]

Hi to all,

<community>
<name>Midtown Plaza Cafe</name>

 The above code is a part of  XML which I am having and I am using the following thing to fetch which is working fine :

st.name = e1.getElementsByTagName("name").item(0).getFirstChild().getNodeValue().trim();

 Now the problem is if  I get a XML like this :

<community>
     </name>

 And if I use the same code to fetch the XML then it is showing me Null error.

 So if any one help on this part.

Thank you,

nimesh

  

[vandzi]

I think, if your error is exception,  u should try to catch it. Problem is that xml is missing open tag <name>. Or try something like this

if(e1.getElementsByTagName("name").item(0) != null){   st.name = .....}

)

[nimesh]

Thank you for your suggestion, I have tried this it same like using try and catch but the issue is that I am having more than 10 Child Nodes than I have to use the same in all of them.

Is there any other way out.

Thank you,

nimesh

[vandzi]

use for(int i = 0;i< e.length;i++){

 here try to catch exeption- not for all nodes,just for actual

}

[nimesh]

The child nodes are of different names like name, address, zip, etc.

So i guess for loop will be difficult on that part.

Thank,

nimesh.

[vandzi]

so make "for( ..) "  for elements not for nodes

[bikas]

Have a look at the xmldemo  (ex: C:\Program Files\Research In Motion\BlackBerry JDE 4.3.0\samples\com\rim\samples\device\xmldemo) example provieded with the JDE.You will get the idea.

Regards

Bikas