Java Development

[bh1r1th]

hi friends,

i have aproblem i am doing a third party application in that application

i have display the images in that app i am showing that same image in different areas.

so in that case i am every time downloading from the net and i am displaying.

it takes to much time to display that images. so how can i avoid this situation

please help me friends.here i don't want to save that image in device or sd card.

how to do this task

[RexDoug]

You could cache the image in a hashtable.  Make the URL of the image the key, and the image as the data object. Then you would consult the hashtable prior to actually attempting to GET the image.

[bh1r1th]

hi thank you

but i don't about hashtable concept

please tell me the another way

otherwise plase send the sample code

[RexDoug]

Did you read the javadocs reference for the class Hashtable?

This is a pretty standard collection class. Are you a java developer?

Hashtable allows you to store a value (an Object) and retrieve it by a key, usually a string.

[developermonkeys]

Hashtable Example:

	Hashtable direccion  = new Hashtable();

	Integer ocho = new Integer(8000);
	direccion.put("calle","Primavera");
	direccion.put("numero", ocho);
	direccion.put("colonia"," La Silla ");
	direccion.put("ciudad"," Monterrey ");
	direccion.put("estado"," Nuevo Leon ");
	direccion.put("pais","Mexico");

        String miciudad  = (String) direccion.get("ciudad");
        String miestado  = (String) direccion.get("estado");
	String micalle = (String) direccion.get("calle");
	Integer minumero = (Integer) direccion.get("numero");

	System.out.println("Direccion : " + micalle + " " + minumero);
	System.out.println("Lugar: " + miciudad + "," + miestado);

[welsenKiriono · Accepted solution]

As far as i know, If you want to save your image , you can use these methods

1. hashtable

2. database (using BLOB)

3. file in SDCard or Device (Using FileConnection)

Correct me if i'm wrong...

[bh1r1th]

Thank you for the replay.

welsenKirino your correct.

[bh1r1th]

Thank you

developermonkeys.

Thank you for the valuable code.