Java Development

[myquestion]

String array={"aaaa","bbb","cc*%&vvc"};

how will remove the   *%&    from the required above string.

Please help with a piece of code.

Thanks in advance.

[simon_hain]

indexof and substring, both methods of the String class

[myquestion]

Can you provide a code for this..

Thanks in advance

[simon_hain]

maybe you start with a "java in 21 days" book or something similar?

[Ted_Hopp]

Your requirement isn't very well defined. For instance, this will work:

array[2] = "ccvvc";

but I suspect that you are looking to solve a more general problem. But what problem? If you want to remove all occurences of the characters '*', '%', or '&', then take a look at StringUtilities.removeChars. If you want to remove the character sequence "*%&", then using String.indexOf and substring as Simon suggests is the way to go. However, you need to define what should happen if you start with something like "cc*%&vvc*%&vvc" (which one(s) to remove?). Or even "cc**%&%&vvc" (there's only one occurrence of "*%&", but after it's removed, all of a sudden there's another one!)

[peter_strange]

I think Simon's point is valid.  This is a Java question and would perhaps be better directed at a forum that is specifically for Java.  In addition, if someone can't create a piece of Java code that uses substring and indexOf, then perhaps a course is needed.

[DAquilina]

I'm afraid I don't have any links for Java newbies at the moment. But if you Google "Introduction to Java" I'm sure there are a few good online tutorials out there (Who reads these days? )

Good luck,

~Dom

PS - String array={"aaaa","bbb","cc*%&vvc"}; is improper syntax --

You would get a compiler error because you forgot to include the square brackets ('[' and ']') to indicate that it is an array. Try:

String [] array = { "aaaa", "bbb", "cc*%&vvc" };

Then, to remove '*%&'...

String s = array [2];
String s2 = *%&;

s = s.substring (0, s.indexOf (s2)) //"cc"
s += s.substring (s.indexOf (s2) + s2.Length, s.Length () - (s.indexOf (s2) + s2.Length ())); //"cc" + "vvc"

array [2] = s;

That's a pretty ugly snippet, but basically what it's doing is removing the unwanted segment by creating a new string which is the first segment, "cc", plus the end segment, "vvc".