Welcome!

Welcome to the official BlackBerry Support Community Forums.

This is your resource to discuss support topics with your peers, and learn from each other.

inside custom component

Java Development

Reply
Highlighted
Contributor
Posts: 16
Registered: ‎07-30-2012
My Device: None
My Carrier: Proximus
Accepted Solution

Character.digit()

Hi folks,

 

My goal is to convert a character (for exaple 'A') to the decimal ascii value ( = 65).

Im aware that I have to use  Character.digit('A',int radius);  But my question is: what does the radius value have to be to get 65 returned? I tried 10 (decimal) but I get always -1 returned.

 

And yes, I googled. But nothing.

 

Thanks!

Developer
Posts: 16,984
Registered: ‎07-29-2008
My Device: Z10 LE, Z30, Passport
My Carrier: O2 Germany

Re: Character.digit()

much easier to cast it to int, it is a char, after all.
(int)'A' is 65, for example.
----------------------------------------------------------
feel free to press the like button on the right side to thank the user that helped you.
please mark posts as solved if you found a solution.
@SimonHain on twitter
Developer
Posts: 434
Registered: ‎07-23-2012
My Device: Blackberry 10
My Carrier: Orange

Re: Character.digit()

try
{
int myint = (int) mychar;
}catch(NumberFormatException e)
{
//Do whatever you want with it!
}

Thanks
-------------------------------------------------------------------------------------
Press the Accept as solution Button when u got the Solution
Press Kudo to say thank to developer.
-------------------------------------------------------------------------------------.
Developer
Posts: 19,636
Registered: ‎07-14-2008
My Device: Not Specified

Re: Character.digit()

I would ignore the previous post, it is not possible for a cast to throw a NumberFormatException.